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!68 修复 NumberUtil.isNumber 方法
Merge pull request !68 from jonzhang-3/v4-dev
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3ff93c2914
@ -1059,9 +1059,9 @@ public class NumberUtil {
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boolean allowSigns = false;
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boolean foundDigit = false;
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// deal with any possible sign up front
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int start = (chars[0] == '-') ? 1 : 0;
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int start = (chars[0] == '-' || chars[0] == '+') ? 1 : 0;
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if (sz > start + 1) {
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if (chars[start] == '0' && chars[start + 1] == 'x') {
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if (chars[start] == '0' && (chars[start + 1] == 'x' || chars[start + 1] == 'X')) {
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int i = start + 2;
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if (i == sz) {
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return false; // str == "0x"
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@ -66,6 +66,9 @@ public class NumberUtilTest {
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public void isNumberTest() {
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Assert.assertTrue(NumberUtil.isNumber("28.55"));
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Assert.assertTrue(NumberUtil.isNumber("0"));
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Assert.assertTrue(NumberUtil.isNumber("+100.10"));
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Assert.assertTrue(NumberUtil.isNumber("-22.022"));
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Assert.assertTrue(NumberUtil.isNumber("0X22"));
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}
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@Test
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